Can a small yolk sac lead to embryonic arrest?

　　A small gestational sac may lead to fetal arrest. The detailed analysis is as follows:

　　A small gestational sac refers to a situation in early pregnancy where embryonic development stops and growth ceases. A small gestational sac may result in fetal arrest, meaning the embryo stops developing inside the uterus, ultimately leading to spontaneous miscarriage, which typically occurs within the first eight weeks after the embryo implants in the uterine lining. Under normal circumstances, the embryo should rapidly develop into a fetus with a heartbeat and other vital organs. However, if problems arise during development, embryonic growth may stall. The exact cause of a small gestational sac remains unclear, but it may be associated with various factors, including chromosomal abnormalities, abnormal embryonic development, maternal malnutrition, and advanced maternal age. Additionally, maternal smoking, alcohol consumption, chronic diseases, or certain medications may increase the risk of a small gestational sac. Often, a small gestational sac presents no obvious symptoms; pregnant women may notice the disappearance of early pregnancy symptoms or the absence of fetal heartbeat. If a small gestational sac is suspected, doctors usually recommend an ultrasound examination to confirm the diagnosis. An ultrasound can assess the size and developmental status of the embryo and detect whether a fetal heartbeat is present. Once a small gestational sac is diagnosed, doctors typically advise either allowing natural miscarriage or undergoing surgical intervention.

　　When dealing with this condition, pregnant women need appropriate psychological support, including communication with family and friends, seeking professional counseling, or joining support groups. With adequate support and understanding, women can better cope with this loss and gradually recover both physically and emotionally.